[湮灭PVE] 湮灭龙希尔狂龙之怒时长可能最大值与急速关系[施工中] - 魔兽世界玩家社区APP官网

#include <iostream>
#include <fstream>
using namespace std;
#define RSC 30
#define Animosity Dragonrage_time += 6
ofstream outfile;
void RunSim(double haste,bool bloodlust,bool feedthefalmes,bool causality,bool hoardedpower)//急速，嗜血，火上浇油，因果律,贮藏能量
{
double Dragonrage_time = 14,gcd=bloodlust?(1.5/(1+(0.3+haste*0.01*1.3))):1.5 /(1 + 0.01 * haste), Firebreath_cooldown = 0, EternitySurge_cooldown = 0, Runtime = 0;
int EssenceBurst=0, EssenceBurst_count=0, Firebreath_count=1, EternitySurge_count=1;
Runtime += 2 * gcd;
Dragonrage_time += 12;
EternitySurge_cooldown = RSC-gcd;
Firebreath_cooldown = RSC;
while ((Runtime+1/(1+haste)) < Dragonrage_time)
{
if(bloodlust && (Runtime > 30))
{
bloodlust = 0;
gcd = 1.5 / (1 + 0.01 * haste);
}
if (Firebreath_cooldown < gcd)
{
Animosity;
EternitySurge_cooldown-=gcd;
Runtime += gcd+((Firebreath_cooldown>0)? Firebreath_cooldown:0);
Firebreath_cooldown = 30;
Firebreath_count++;
continue;
}else
if (EternitySurge_cooldown < gcd)
{
Animosity;
Firebreath_cooldown -= gcd;
Runtime += gcd + ((EternitySurge_cooldown > 0) ? EternitySurge_cooldown : 0);
EternitySurge_cooldown = 30;
EternitySurge_count++;
continue;
}
else
{
if (EssenceBurst)
{
EssenceBurst_count++;
EssenceBurst--;
if (hoardedpower && ((double(rand())/3267)<=0.2)) EssenceBurst++;
if(feedthefalmes) Firebreath_cooldown -= 2;
if(causality)EternitySurge_cooldown -= 1.43;
}
else EssenceBurst++;
Runtime += gcd;
Firebreath_cooldown -= gcd;
EternitySurge_cooldown -= gcd;
}
}
//cout << haste << " " << Dragonrage_time << " " << Firebreath_count << " " << EternitySurge_count << " " << EssenceBurst_count << "\n";
outfile<< Dragonrage_time << "\n";
return;
}
int main()
{
outfile.open("calculate.txt");
for (int i = 0; i <= 100;i++)
RunSim(i,1,0,1,0);
outfile.close();
return 0;
}

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5豆结论貌似有点错误，算上初始5豆，左边还要减去2.5x，那么50秒狂龙的结论应该是单体57.9%急速与aoe42.11%急速，anyhow，急速22-25%应该是绿字富裕后不错的选择另外如果用我的方法进行计算，那么续到38秒急速-37%都够(初始5豆条件)，无豆的话就是-17%急速，但是这就和LZ结论冲突了，但是实验证明aoe环境开SX 急速22%续到50秒是很稳的，我估计我和LZ的计算各有对错

只有一张表吗，单体环境和AOE可是不一样的，AOE环境你葬火+动燃可以多次触发永恒之涌的减CD，算期望的话AOE环境里葬火对永恒之涌的减CD效率比单体环境要高42.8571%另外有没有考虑到豆子本身的回复？我看LZ貌似是用A+B循环模型建模的，除了免费的A+B模式外还能用豆子打不免费的葬火，形成B+B+A+A+A循环，不免费的葬火仅减少永恒之涌的CD，而豆子的回复还要算上那个回复天赋，这就有点复杂，不过脑测一下我觉得误差不会大于一个GCD，另外他这个豆子回复很不一样，设5个豆子分别为ABCD